bourgeois passing Markham …

I agree the oracle site isn’t the easiest one but…
I just wanted to say you can always ask tom about oracle.

http://asktom.oracle.com

Pim

I’ve just created a table news on an oracle 8.1.7 install I’ve access to. I’ve inserted 10 test records:

SQL> select * from news;

ID DATE_CREA NAME
— ——— ——————–
1 19-MAY-06 test 1 – 100
2 29-MAY-06 test 2 – 90
3 08-JUN-06 test 3 – 80
4 18-JUN-06 test 4 – 70
5 28-JUN-06 test 5 – 60
6 08-JUL-06 test 6 – 50
7 18-JUL-06 test 7 – 40
8 28-JUL-06 test 8 – 30
9 07-AUG-06 test 9 – 20
10 17-AUG-06 test 10 – 10

Now the result of your query:

ID DATE_CREA NAME NUMERO
— ——— ——————– ——
5 28-JUN-06 test 5 – 60 5
4 18-JUN-06 test 4 – 70 4
3 08-JUN-06 test 3 – 80 3
2 29-MAY-06 test 2 – 90 2
1 19-MAY-06 test 1 – 100 1

That does not seem to be correct, does it? I would expect id 10 to 6 to show up, not 5 to 1.

I also verified this with a clean oracle 10 XE install, and it gives me the same results.

There is however an alternave for the solution I gave. You could also use:

SELECT *
FROM (
SELECT n.*
, row_number() over (order by date_created desc)
as numero
FROM news n
)
WHERE
numero

Your LIMIT example is incorrect. The ROWNUM field is added to the query BEFORE it’s sorted. So if a not ordered select will give you the newest 5 articles it will work, but that is not a guarenteed situation.

You example should have been:

SELECT *
FROM (
SELECT n.*
FROM news n
ORDER BY date_created DESC
)
WHERE
ROWNUM

brian.tully at gmail.com

thanks again.

Do you have any good references (books/sites) for getting up to speed on Oracle, especially coming from a MySQL background? It would be GREATLY appreciated.

Another option would be if anyone knows of an experienced Oracle developer that has some free time and familiarity with iLearning. We definitely could use some help ASAP.

Thanks again…